Distance from Start z 60 cm Distance from Start x -80 cm Readings Abs. Time for Glider to Travel its Own Length on Track (sec) Distance from Start X-eorm | Distance from start x peEm Readings 01099 O.L 102 C.15 46 0.1696 Abs. Deviation 8.2 Ocm Cm Cm 9.6 cm, CVwm 80 Cm Average Y 2cm Average9 Mean Dev. Angle of the Inclined Plane (Air Track) Y Values (cm) X Values (cm) ReadingsAbs.Deviation Readings Abs. Length of Glider - Ruler Readings from em) Left EndRight End Length (cm) Mean C Absolute from the (cm) toc Average Value ot Lengthm cm Deviation 3. How can some of these errors be eliminated?Ģ. Would they make your results too high or too low? 2. Make a list of the systematic errors that might have affected your values of a. Find the percent difference between the theoretical value and the experimental value of the acceleration, a. Calculate the value of the acceleration and tension from equations (3) and (4). c) Use the equation of the curve to find the acceleration a. b) Find the equation of the curve of best fit.

a) After the input of data, Double Click on Scatter Graph. (V2 is vertical axis x is horizontal axis.) The slope of this graph gives the acceleration. Use the Cricket graph software and the Macintosh computer to plot the data: velocity square, V2, versus x. Find the velocity squared, V2, and its mean deviation, which is given by 6.

The mean deviationi the velocity is given byĥ. Use the average time t and the average length L in order to find the velocity, the glider had as it past the photocell for each distance x. Find the average value of the length, L, of the glider Mi, and the mean e average value of the length, L, of the glider M1, and the mean deviation Find the average value of the time that it takes for the glider pass through the photocell, and the mean deviation of each time, for each distance. The relative mean deviation is the mean deviation divided by the average. Note: The mean deviation is the average of the absolute values of the individual deviations from the average. the average value of the masses Mı and M2, and the mean deviations.

321.0 cm NOTE: Use StatView II software and computer for this analysis.

Velocity Squared length | Time |Velocity | Mean Deviation 86 6 and Mean Deviation Versus Distance Squared Velocity Distance x (cm) 6254 8 O gO 121y 72.49 8.80 0633 131.

Statview 5 0 software developer